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 Hex and Binary Binary (Power of 2) 2 to the 0 = 1             2 to the 12th = 4096 2 to the 1st = 2           2 to the 13th = 8192 2 to the 2nd = 4          2 to the 14th = 16384 2 to the 3rd = 8           2 to the 15th = 32768 2 to the 4th = 16         2 to the 16th = 65536 2 to the 5th = 32         2 to the 17th = 131072 2 to the 6th = 64         2 to the 18th = 262144 2 to the 7th = 128        2 to the 19th = 524288 2 to the 8th = 256        2 to the 20th = 1048576 2 to the 9th = 512        2 to the 21st = 2097152 2 to the 10th = 1024     2 to the 22nd = 4194304 2 to the 11th = 2048 I only go up to 2 to the 22nd because that is the maximum number of bits that can be borrowed when subnetting. (Borrowing 22 bits from a Class A address will give us 4,194,302 networks. 4194304 -2) HEX (Power of 16) 0 1 2 3 4 5 6 7 8 9 A(10) B(11) C(12) D(13) E(14) F(15) Convert 17 DEC to HEX convert to binary first 00010001 = 17 break down in groups of 4 0001 | 0001 convert each group of 4 to HEX 0001 = 1 | 0001 = 1 combine the results left to right (DO NOT add) 17 DEC = 11 HEX Convert 58 DEC to HEX 00111010 = 58 0011 | 1010 0011 =3 1010 = A 58 DEC = 3A HEX Convert 765 DEC to HEX 1011111101 = 765 To make even groups of 4, you must add leading zeros 001011111101 then break down into groups of 4 0010 | 1111 | 1101 0010 = 2 1111 = F 1101 = D 765 Dec = 2FD Hex Convert HEX to DEC 3A to DEC First convert to binary 3 = 00000011 A(10) = 00001010 starting with the first number (3), take only the significant digits - 11 then the significant digits from the second number - 1010 then combine them (from left to right) 111010 then convert to DEC 32+16+8+2 = 58 Convert BAD to Dec. B = 11 = 00001011 A = 10 = 00001010 D = 13 = 00001101 101110101101 = 2989 Dec